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TEST DATE : 09 OCT 2005
LOCATION : CHRIST COLLEGE, BANGALORE
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Infosys Question –October (9/10/2005)Bangalore-Christ
College
I was shortlised in the written test and I
attended the interview .Hopefully waiting for the result. And one more
thing, they r checking the rough work so don’t by heart and
write. Those who attended the interview please inform me as soon
as u get the result in this batch
1.There are 100 students among them 10 dont study
both physics and chemistry,63 studying physics,85 studying
chemistry. how many of them are studying both chemistry and physics
(3 mark)
ans; 63+85-90=68
2. sal and saul are taking part in 100 yards running race in which sal
beats saul by 10 yards. If sal starts 10 yards behind the starting
line who will win the race?
Ans;sal wins saul by 1 yard, because
as sal covers 10 yards saul covers only 9 yards.
3.This problem is like .....
IF A= 4,A+B+C+D = D+E+G+H=G+H+I=17..
whats the value of D and G.
(6 mark)
ans; d=5 g=1
4.In a dice the nos 1&6, 2&5,
3&4 are to be in opposite face . how many chances are there to
attain this by satisfying
the above condition....
(3 mark)
Ans: 48(u need to place the nos in the die in such a way it
satisfies all the condition i.e. right-1 left-6 top-2 bottom-5 front-3
back-4
5.In this problem , they gave 6 equations
..
like M+E=1000
E+C=4000..
.....
....
.....
....
....
upto 6 equations..
(8 mark)
and ask us to find out the value of each variable. in this type of
problem just cancel the common variables in given equation by either
addition or subtraction.
6.there are two cans A&B can A contains water, can B contains pure
milk .first double the amount of liquid in can B by adding water from
can A , the double the content of can A by adding content of can B,
then finally double the amount of can B by can A at last the amount in
both the cans are equal and the water in can B is 1 gallon more the
amount of milk .find the amount of milk &water start with. (6
mark)
(I was not able to solve this problem if any
one can plz send me the soln)
7.Jan robinson, kate jones, john smith are
engineer, pilot & biochemist not in the order .they have three
martian assistants . as they find difficulty with martian names they
gave them nick names as smith, robinson, jones as their masters name.
1.robinson is an yomi
2.all martians speak uri.
3.the martians name is the same as the bio
chemist is naim
4.robinson beats engineer in the chess
(one more condition) who is the pilot?
dont remember exactly..
Ans :Jan robinson
8. This problem was to arrange 7 gems in right & left window 3 in
each very easy ..this question carries 8 marks...
Its easy.... U can do it..
9.a parent has 15 children who where born in an interval of 1.5 years
each . the first child`s age is 8 times that of last child. what’s
the age of the first child?.(4M)
Ans:
X=8Y, X=Y+21 Solving X=24
10.Sita goes to Gita's house during vacation. they
play a game of chess everyday and the loser has to
give
a chocolate to the winner for every game . Sita
gave 8 chocolates to Gita at the end of the vacation,
although she had won 12 games. How long did she stay
there? 5 marks
Ans : 32 days(doubt)I
put as 31
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